if `sin(alpha+beta)=1 and sin(alpha-beta)=1/2 " "0lealpha,beta,lepi/2,then` find `tan(alpha+2beta)and tan(2alpha+beta)`

sin(alpha+beta)=1 and sin(alpha-beta)=(1)/(2)quad 0<=alpha,beta,<=(pi)/(2), then find tan(alpha+2 beta) and tan(2 alpha+beta)

If sin(alpha+beta)=1,sin(alpha-beta)=(1)/(2) where alpha,beta in[0,(pi)/(2)], then tan(alpha+2 beta)tan(2 alpha+beta) is equal to

If sin(alpha+beta)=1 and sin(alpha-beta)=(1)/(2), where 0<=,beta<=(pi)/(2) ,then find the values of tan(alpha+2 beta) and tan(2 alpha+beta)

If sin (alpha + beta)=1, sin (alpha- beta)= (1)/(2) , then tan (alpha + 2beta) tan (2alpha + beta) =

If : sin (alpha + beta)=1 and sin (alpha-beta)=(1)/(2), "then" : tan (alpha+2beta)*tan(2alpha+beta)= A)-1 B)0 C)1 D)2

If sin(alpha+beta)=1,sin(alpha-beta)=(1)/(2) then tan(alpha+2 beta)tan(2 alpha+beta)=

If cos(alpha+beta)+sin(alpha-beta)=0 and tan beta ne1 , then find the value of tan alpha .

If 3 sin beta=sin(2alpha+beta) , then tan (alpha+beta)-2 tan alpha is

If sin alpha+sin beta=a and cos alpha-cos beta=b then tan((alpha-beta)/(2))=