Show that: `1/(sec A-tan A) - 1/(cos A) = 1/(cos A) - 1/(sec A + tan A)`

Show that (i) sin^(8)A-cos^(8)A=(sin^(2)A-cos^(2)A)(1-2sin^(2)A.cos^(2)A) (ii) (1)/(sec A-tan A)-(1)/(cos A)=(1)/(cos A)-(1)/(sec A + tan A)

Prove the trigonometric identities: (1)/( sec A+tan A)-(1)/(cos A)=(1)/(cos A)-(1)/(sec A-tan A)

(1)/( sec x- tan x ) - ( 1)/( cos x ) = ( 1)/( cos x ) - ( 1)/( sec x + tan x )

(1 + sec A + tan A) (1-cos eA + cot A) = 2

Prove that (sinA -cos A+1)/(sin A + cos A - 1) = (1)/(sec A - tan A)

Show that sec A(1-sin A)(sec A+tan A)=1

1/(sec A + tan A) = sec A - tan A

(tan A)/(1+sec A)-(tan A)/(1-sec A)=2cosec A

(sin A)/(sec A+tan A-1)+(cos A)/(cos ecA+cot A-1)=1

Prove that (1+sec A-tan A)/(1+sec A+tan A)=1-sin A/(cos A)