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If (cos^4A)/(cos^2B)+(sin^4A)/(sin^2B)=1...

If `(cos^4A)/(cos^2B)+(sin^4A)/(sin^2B)=1` then prove that `sin^4A+sin^4B=2sin^2Asin^2B` `(cos^4B)/(cos^2A)+(sin^4B)/(sin^2A)=1`

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