`(2 sin theta*cos theta - cos theta)/(1-sin theta+sin^2 theta-cos^2 theta) = cot theta`

(sin3 theta+cos3 theta)/(cos theta-sin theta)=1+2xx sin2 theta

(sin3 theta-sin theta)/(cos theta-cos3 theta)=cot2 theta

2(cos theta+cos2 theta)+(1+2cos theta)sin2 theta=2sin theta

Prove that: (sin2 theta)/(1-cos2 theta)=cot theta

Prove that: ((1)/(cos theta)-(1)/(sin theta))(1+(sin theta)/(cos theta)+(cos theta)/(sin theta))=sec theta tan theta-cosec theta cot theta

(sin3 theta-sin theta sin^(2)(2 theta))/(sin theta+sin2 theta cos theta)=cos x then x=

The value of (cos^6 theta+sin^6 theta+ 3sin^2 theta cos^2 theta)/(cosec theta sec theta(sin theta+cos theta-1)(sin theta+cos theta+1)) is : (cos^6 theta+sin^6 theta+ 3sin^2 theta cos^2 theta)/(cosec theta sec theta(sin theta+cos theta-1)(sin theta+cos theta+1)) का मान ज्ञात कीजिए?

(sin theta)/(cot theta+cos ec theta)-(sin theta)/(cot theta-cos ec theta)=

Prove that (cos theta-sin theta+1)/(cos theta+sin theta-1)=csc theta+cot theta