If `tan theta + cot theta` = 2 find `sin theta` ?

If tan theta+cot theta=2 then sin theta+cos theta=

Prove that : tan theta - cot theta = (2 sin^(2) theta - 1)/(sin theta cos theta)

If tan theta-cot theta=alpha and sin theta+cos theta=b then (b^(2)-1)^(2)(a^(2)+4) is

If tan theta-cot theta=a and sin theta+cos theta=b ,then (b^(2)-1)^(2) . (a^(2)+4)=

If tan theta+cot theta=2, find the value of tan^(2)theta+cot^(2)theta

If tan theta+cot theta=6 , then find the value of tan^2 theta+cot^2 theta . यदि tan theta+cot theta=6 , तो tan^2 theta+cot^2 theta का मान ज्ञात कीजिए।

If tan theta+cot theta=4 , then find the value of tan^(4)theta+cot^(4)theta .

If theta be acute and tan theta + cot theta = 2 , then the value of tan^5 theta+ cot^10 theta is

tan theta-cot theta=a and sin theta+cos theta=b(b^(2)-1)^(2)(a^(2)+4)

If theta is an acute angle and tan theta+cot theta=2 find the value of tan^(7)theta+cot^(7)theta