If `sintheta +cos theta =m` and `sec theta + cosec theta =n` then `n(m+1)(m-1)` equals

If sin theta+cos theta=m and sec theta+cos ec theta=n then n(m+1)(m-1) equals

If sin theta + cos theta = m and sec theta + "cosec" theta = n, prove that n(m^(2)-1) = 2m.

If cos theta + sin theta = m , sec theta + cosec theta =n , What is m//n ?

If "cosec" theta - sin theta = m and sec theta - cos theta = n, then find a relation between m and n, independent of theta .

If "cosec" theta - sin theta = m and sec theta - cos theta = n, then what is m^(4/3) n^(2/3) +m^(2/3) n^(4/3) equal to ?

If cos theta+sin theta=m and sec theta+csc theta=n,then(2m^(2))/((m^(2)-1)^(2))=?

If costheta+sintheta=mandsectheta+"cosec"theta=n then the value of n (m^(2)-1) is equal to :

If tan theta + sin theta = m , tan theta - sin theta = n then m^(2) -n^(2) is equal