`tan(alpha+beta)tan(alpha-beta)=(sin^2 alpha-sin^2 beta)/(cos^2 alpha-sin^2 beta)`

If tan theta=(tan alpha+tan beta)/(1+tan alpha tan beta) then show that sin2 theta=(sin2 alpha+sin2 beta)/(1+sin2 alpha sin2 beta)

Prove that: cos2 alpha cos2 beta+sin^(2)(alpha-beta)-sin^(2)(alpha+beta)=cos2(alpha+beta)

(cos alpha + cos beta)/( sin alpha - sin beta) + (sin alpha + sin beta)/( cos alpha - cos beta ) =

If sin(alpha+beta)=1,sin(alpha-beta)=(1)/(2) then tan(alpha+2 beta)tan(2 alpha+beta)=

tan ^ (2) alpha-tan ^ (2) beta = (sin ^ (2) alpha-sin ^ (2) beta) / (cos ^ (2) alpha cos ^ (2) beta)

2sin^(2)beta+4cos(alpha+beta)sin alpha sin beta+cos2(alpha+beta)=

The value of sin^2 alpha cos^2 beta + cos^2 alpha sin^2 beta + sin^2 alpha sin^2 beta +cos^2 alpha cos^2 beta is

If tan (alpha-beta)=(sin 2beta)/(3-cos 2beta) , then