If a right angle be divided into three parts `alpha, beta and gamma`, prove that `cot alpha = (tan beta + tan gamma)/(1-tan beta tan gamma)`.

A right angle is divided into three positive parts alpha,beta and gamma. Prove that for all possible divisions tan alpha+tan beta+tan gamma>1+tan alpha tan beta tan gamma

If alpha+ beta + gamma=90^(@) , then tan alpha+ tan beta + tan alpha tan beta cot gamma is __________

If alpha+beta+gamma=2pi , then show that tan.alpha/2 + tan.beta/2 + tan.gamma/2 = tan.alpha/2 tan.beta/2 tan.gamma/2 .

If alpha,beta,gamma are acute angle such that cos alpha=tan beta,cos beta=tan gamma and cos gamma=tan alpha then

If alpha+beta=(pi)/(2) and beta+gamma=alpha then tan alpha equals (A) 2(tan beta+tan gamma)(B)tan beta+tan alpha (C) tan beta+2tan gamma(D)2tan beta+tan gamma

If alpha+beta=(pi)/(2) and beta+gamma=alpha then tan alpha equals (A) 2(tan beta+tan gamma)(B)tan beta+tan alpha (C) tan beta+2tan gamma(D)2tan beta+tan gamma

Prove that (tan alpha+tan beta)/(cot alpha+cot beta)=tan alpha tan beta

If 2tan beta+cot beta=tan alpha, prove that cot beta=2tan(alpha-beta)

Let alpha=som^(-1)((36)/(85)),beta=cos^(-1)((4)/(5)) and gamma=tan^(-1)((8)/(15)) then cot alpha+cot beta+cot gamma=cot alpha cot beta cot gammatan alpha tan beta+tan beta tan gamma+tan alpha tan gamma=1tan alpha+tan beta+tan gamma=tan alpha tan beta tan gammacot alpha cot beta+cot beta cot gamma+cot alpha cot gamma=1