Show that: `s in(B-C)cos(A-D)+sin(C-A)cos(B-D)+sin(A-B)cos(C-D)=0`

Show that: sin(B-C)cos(A-D)+sin(C-A)cos(B-D)+sin(A-B)cos(C-D)

Prove that: sin(B-C)cos(A-D)+sin(C-A)cos(B-D)+sin(A-B)cos(C-D)

cos(A-D)sin(B-C)+cos(B-D)sin(C-A)+cos(C-D)sin(A-B)=0

What is the value of sin (B - C) cos (A- D) + sin (A-B) cos (C -D) + sin (C- A) cos (B - D) ? sin (B - C) cos (A- D) + sin (A-B) cos (C -D) + sin (C- A) cos (B - D) का मान क्या है?

If : x=sin(B-C) * cos A, y=sin(C-A) * cos B, z=sin(A-B) * cos C, then : x+y+z= (a) sin(A-B-C) (b) cos(A-B-C) (c)0 (d)-1

In a ABC, prove that sin^(3)A cos(B-C)+sin^(3)B cos(C-A)+sin^(3)C cos(A-B)=3s in As in Bs in

If A, B, C, D are four angles then sin (AB) .cos (A + B) + sin (BC) .cos (B + C) + sin (CD) .cos (C + D) + sin ( DA) .cos (D + A) =

Prove that (sin(B-C))/(cos B cos C)+(sin(C-A))/(cos C cos A)+(sin(A-B))/(cos A cos B)=0

Prove that: (sin(B-C))/(cos B cos C)+(sin(C-A))/(cos C cos A)+(sin(A-B))/(cos A cos B)=0

In equilibrium ABCD, prove thatL: i) sin(A+B)+sin(C+D)=0 ii) cos(A+D)-cos(B+C)=0