`(cos(A-B))/(cos(A+B))+cos(C+D)/(cos(C-D))=0 => tan A tan B tan C tan D =`

If (cos(A-B))/(cos(A+B))+(cos(C+D))/(cos(C-D))=0, prove tht tan A tan B tan C tan D=-1

(cos (AB)) / (cos (A + B)) + (cos (C + D)) / (cos (CD)) = 0rArr tan A tan B tan C tan D =

(cos(A+B))/(cos(A-B))+(cos(C-D))/(cos(C+D))=0rArr cot A cot B cot C cot D=

(cos(A+B))/(cos(A-B))+(cos(C-D))/(cos(C+D))=0rArr cot A cot B cot C=

If (cos (AB)) / (cos (A + B)) + (cos (C + D)) / (cos (CD)) = 0 Prove that tan A tan B tan C tan D = -1

If cos2B=(cos(A+C))/(cos(A-C)) , then tan A, tan B, tan C are in

If cos2B=(cos(A+C))/(cos(A-C)), then tan A,tan B,tan C are in

If (cos(A-B))/(cos(A+B))=(8)/(3) then tan A tan B is

If (" cos " (A+B))/(" cos " (A-B)) =(" sin " (C+D))/(" sin " (C -D)) , prove that tan A tan B tan C + tan D=0

If cos(A+B) sin (C-D) = cos (A-B) sin (C+D) , then show that tan A tan B tan C + tan D =0