Let `(3pi)/4 < theta < pi` and `sqrt(2 cot theta+1/sin^2 theta) = k - cot theta` then `k=`

Let (3 pi)/(4)

Let f(x) =sinx + 2 cos^(2)x (pi)/(4)lt=x lt= (3pi)/(4) . Then f attains its

Let the domain and range of inverse circular functions are defined as follows: sin^(-1)xlt(3pi)/4 then solution of x is

Let cos(pi)/(7),cos(3 pi)/(7),cos(5 pi)/(7) are the roots of equation 8x^(3)-4x^(2)-4x+1=0 Q.The value of sec((pi)/(7))+sec((3 pi)/(7))+sec((5 pi)/(7)) is

tan ((pi)/(4)+theta) tan ((3pi)/( 4) + theta) is equal to

The range of the function f(x) = log_(sqrt5)(3 + cos ((3pi)/4 + x) + cos ((pi)/4 + x) + cos ((pi)/4 - x) - cos ((3pi)/4 - x)) is :

The range of the function f(x) = log_(sqrt5)(3 + cos ((3pi)/4 + x) + cos ((pi)/4 + x) + cos ((pi)/4 - x) - cos ((3pi)/4 - x)) is :

Let veca,vecb and vecc be three unit vectors such that vecaxx(vecbxxvecc)=sqrt(3)/2(vecb+vecc) . If vecb is not parallel to vecc then the angle between veca and vecb is (A) (5pi)/6 (B) (3pi)/4 (C) pi/2 (D) (2pi)/3

For f(x)=sin^2x ,x in (0,pi) point of inflection is: pi/6 (b) (2pi)/4 (c) (3pi)/4 (d) (4pi)/3