Using induction, prove that `cos theta · cos 2theta · cos 2^2 theta. ... cos 2^(n-1) theta =(sin2^n theta)/(2^n sin theta)`

Similar Questions

Explore conceptually related problems

Using induction,prove that cos theta cos2 theta cos2^(2)theta...cos2^(n-1)theta=(sin2^(n)theta)/(2^(n)sin theta)

cos theta+cos2 theta+cos3 theta+......+cos(n-1)theta+cos n theta=

Prove that : cos ec theta+cos ec2 theta+cos ec2^(2)theta+.........+cos ec2^(n-1)theta=cot((theta)/(2))-cot2^(n-)

Prove that: sin^(6) theta + cos^(6) theta =1 - 3 sin^(2) theta cos^(2) theta

Prove that : sin^(4)theta + cos^(4)theta = 1 - 2 cos^(2) theta + 2 cos^(4)theta

If theta=(pi)/(2^(n)+1), prove that: 2^(n)cos theta cos2 theta cos2^(2)...*cos2^(n-1)theta=1

Prove that: (sin2 theta)/(1-cos2 theta)=cot theta

cos theta+sin theta=cos2 theta+sin2 theta

Prove that : (sin^(2) theta)/(cos theta ) + cos theta = sec theta