Prove that : `sin theta cos^3 theta - cos theta sin^3 theta = 1/4 sin4theta`.

Prove that sin theta cos^(3)theta - cos theta sin^(3) theta = (1)/(4) sin 4 theta .

sin theta cos ^ (3) theta-cos theta sin ^ (3) theta = (1) / (4) sin4 theta

(sin3 theta+cos3 theta)/(cos theta-sin theta)=1+2xx sin2 theta

Prove that : (cos4 theta+cos3 theta+cos2 theta)/(sin4 theta+sin3 theta+sin2 theta)=cot3 theta

sin 7 theta * sin theta+sin11theta * sin 3theta= A) sin 4 theta * sin 10theta B) cos 4 theta * cos 10 theta C) sin 8 theta * sin 4 theta D) cos 8 theta * cos 14 theta

Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

Prove the following: 2^(3)sin theta cos theta cos2 theta cos4 theta=sin8 theta

Prove that : sin theta/cos(3theta) +sin (3theta)/cos (9theta) + sin(9theta)/cos( 27theta )= 1/2(tan27 theta -tan theta)

Solve sin^(3)theta cos theta-cos^(3)theta sin theta=(1)/(4)