`sin(pi/5) sin((2pi)/5) sin((3pi)/5) sin((4pi)/5)=`

The value of 2 sin (pi/8) sin((2pi)/8) sin((3pi)/8) sin ((5pi)/8) sin ((6pi)/8) sin((7pi)/8) is :

2sin((pi)/8)sin((2pi)/8)sin((3pi)/8)sin((5pi)/8)sin((6pi)/8)sin((7pi)/8) = ?

bb"Statement I" The range of f(x)=sin(pi/5+x)-sin(pi/5-x)-sin((2pi)/5+x)+sin((2pi)/5-x) is [-1,1]. bb"Statement II " cos""pi/5-cos""(2pi)/5=1/2

Prove that: (sin pi)/(5)(sin(2 pi))/(5)(sin(3 pi))/(5)(sin(4 pi))/(5)=(5)/(16)

sin ((pi) / (5)) sin ((2 pi) / (5)) sin ((3 pi) / (5)) sin ((4 pi) / (5)) =

sin((13pi)/3)sin((8pi)/3)+cos((2pi)/3)sin((5pi)/6)=1/2

sin(pi/18)sin(5 pi/18)sin(7 pi/18)

sin(pi)/(4)*sin(3 pi)/(4)*sin(5 pi)/(4)*sin(7 pi)/(4)=

(sin((2 pi)/(7))+sin((4 pi)/(7)) -sin((6 pi)/(7)))/(sin((pi)/(7))sin((3 pi)/(7))sin((5 pi)/(7))) is equal to

The value of sin (pi/14). sin((3pi)/14). sin( (5pi)/14)………. Sin ((13pi)/14) is