Find the greatest angle of `DeltaABC` if : `a=2, b = sqrt(6), c = sqrt(3) -1`

Find the greatest angle of Delta ABC if: a=m,b=n,c=sqrt(m^(2)+mn+n^(2))

In a DeltaABC if a = 2, b=sqrt(6),c=sqrt(3)+1 , then cos A=

Find the area of DeltaABC , if a=10, b=7sqrt(2) m and sqrt( c)=45^(@)

In a DeltaABC , if a = 3, b=2sqrt(3) and c=sqrt(3) , then A=

In DeltaABC, a=2, b=sqrt(6) and c=sqrt(3)+1 , find angleA .

In a DeltaABC , if c = 2, A=120^(@), a=sqrt(6) , then C=

In a DeltaABC , if A=45^(@) , b=sqrt(6) , a=2, then B=

If a DeltaABC, b=2, C=60^(@), c=sqrt(6) , then a =

With the usual notation in DeltaABC if angle+angle B=120^(@),a=sqrt(3)+1 and =sqrt(3)-1 then the ratio angle A:angleB is

In a DeltaABC , if a = 5, B=45^(@) and c=2sqrt(2) , then b=