The median `AD` of a `DeltaABC` is perpendicular to AB, prove that `tanA + 2tanB=0`

The median AD of a Delta ABC is perpendicular to AB,prove that tan A+2tan B=0

If the median of a triangle through A is perpendicular to AB, then

In the figure, AD is perpendicular to BC, prove that AB+AC gt 2AD .

The median AD of DeltaABC is prodiced upto X such that AD= DX. Prove that squareABXC is a parallelogram.

In a DeltaABC, if median AD is perpendicular to AB, the tan A+2 tan B is equal to

In a DeltaABC , Median AD perpendicular to side BC . Find the value of tanA/tanB

If A+B=pi/4 , prove that: (1+tanA)(1+tanB)=2

In Figure -6 , in an equilateral triangle ABC, AD is perpendicular to BC , BE is perpendicular to AC and CF is perpendicular to AB . Prove that 4 (AD^2 +BE^2 +CF^2)=9AB^2

In DeltaABC , the bisector AD of angleA is perpendicular to side BC (see figure). Show that AB =AC or DeltaABC is isosceles.

In the given figure, the two sides AB and BC, and the median AD of DeltaABC are correspondingly equal to the two sides PQ and QR, and the medium PM of DeltaPQR . Prove that DeltaABC~=DeltaPQR.