In any `DeltaABC`, prove that : `1-tan (A/2) tan (B/2) = (2c)/(a+b+c)`

AI Generated Solution

Similar Questions

Explore conceptually related problems

In DeltaABC , Prove that (s-a) tan (A/2)=(s-b) tan (B/2)=(s-c) tan (C/2)

In any Delta ABC, prove that : ((a-b)/(c))=(tan((A)/(2))-tan((B)/(2)))/(tan((A)/(2))+tan((B)/(2)))

In any Delta ABC, prove that: (a+b-c)/(a+b+c)=tan((A)/(2))tan((B)/(2))

Prove the questions : 1-tan.(A)/(2)tan.(B)/(2) = (2c)/((a+b+c))

In any Delta ABC, prove that :tan((A)/(2)+B)=(c+b)/(c-b)tan((A)/(2))

In any DeltaABC , prove that a^(2)sin(B-C)=(b^(2)-c^(2))sinA

If A+B+C=pi , prove that : tan( A/2) tan (B/2) + tan (B/2 )tan (C/2)+ tan( C/2) tan (A/2) =1

In any triangle ABC , prove that tan ((A-B)/(2))=((a-b)/(a+b))cot (C)/(2) .

In any DeltaABC , prove that a(bcosC-c cosB)=(b^(2)-c^(2))

In DeltaABC , prove that: tan2A + tan2B+tan2C=tan2Atan2Btan2C