`A B C D` is parallelogram and `P` is the point of intersection of its diagonals. If `O` is the origin of reference, show that ` vec O A+ vec O B+ vec O C+ vec O D=4 vec O Pdot`

ABCD is parallelogram and P is the point of intersection of its diagonals.If O is the origin of reference,show that vec OA+vec OB+vec OC+vec OD=4vec OP

If ABCD is a rhombus whose diagonals cut at the origin O, then proved that vec OA+vec OB+vec OC+vec OD+vec O

ABCD is a quadrilateral and E is the point of intersection of the lines joining the middle points of opposite side. Show that the resultant of vec (OA) , vec(OB) , vec(OC) and vec(OD) = 4 vec(OE) , where O is any point.

If G is the intersection of diagonals of a parallelogram ABCD and O is any point, then O vecA + O vec B + O vec C + vec (OD) =

If G is the intersection of diagonals of a parallelogram ABCD and O is any point, then O vecA + O vec B + O vec C + vec (OD) =

If O is a point in space, A B C is a triangle and D , E , F are the mid-points of the sides B C ,C A and A B respectively of the triangle, prove that vec O A + vec O B+ vec O C= vec O D+ vec O E+ vec O Fdot

If E is the intersection point of diagonals of parallelogram ABCD and vec( OA) + vec (OB) + vec (OC) + vec (OD) = xvec (OE) where O is origin then x=

Let ABCD be a plarallelogram whose diagonals intersect at P and let O be the origin.Then prove that vec OA+vec OB+vec OC+vec OD=4vec OP

In a triangle OAC, if B is the mid point of side AC and vec O A= vec a , vec O B= vec b , then what is vec O C ?

Given a regular hexagon ABCDEF with centre o,show that vec OB-vec OA=vec OC-vec OD