`veca,vecb,vecc` are the position vectors of vertices A, B, C respectively of a paralleloram, ABCD, ifnd the position vector of D.

If veca , vecb, vecc are the position vectors of the vertices. A,B,C of a triangle ABC. Then the area of triangle ABC is

If veca, vecb and vecc are the position vectors of the vertices A,B and C. respectively , of triangleABC . Prove that the perpendicualar distance of the vertex A from the base BC of the triangle ABC is (|vecaxxvecb+vecbxxvecc+veccxxveca|)/(|vecc-vecb|)

If veca, vecb, vecc, vecd are the position vectors of points A, B, C and D , respectively referred to the same origin O such that no three of these points are collinear and veca+vecc=vecb+vecd , then prove that quadrilateral ABCD is a parallelogram.

If veca,vecb,vecc are the position vectors oif three non collinear points AS,B,C respectively, show that eperpendicular distance of C ferom the line through A and B is (|vecaxxvecb+vecbxxvecc+veccxxveca|)/(|vecb-veca|)

If veca, vecb and vecc are the position vectors of vertices A,B,C of a Delta ABC, show that the area of triangle ABC is 1/2| veca xx vecb + vecbxx vec c+vec c xx veca|. Deduce the condition for points veca, vecb and vecc to be collinear.

ABCD is a parallelogram, and a,b,c and d are the position vector of vertices A,B,C and D of a parallelogram choose the correct option.

In a DeltaABC , the sides BC, CA and AB are consecutive positive integers in increasing order. Let veca, vecb and vecc are position vectors of the vertices A, B and C respectively. If (vecc-veca).(vecb-vecc)=0 , then the value of |veca xx vecb+vecbxx vecc+vecc xxveca| is equal to

ABCD is parallelogram vecA, vecB, vecC and vecD are the position vectors of vecticles A, B, C, and D with respect to any origin, them: