The vectors `veca and vecb ` are non collinear. Find for what value of x the vectors `vecc=(x-2)veca+vecb and vecd=(2x+1) veca-vecb` are collinear.?

The vectors bara and barb are non-collinear The value of x for which the vectors vecc=(x-2)veca+vecb and vecd=(2x+1)veca-vecb are collinear, is

If veca and vecb are two non collinear unit vectors and |veca+vecb|= sqrt3 , then find the value of (veca- vecb)*(2veca+ vecb)

If veca and vecb are two non collinear unit vectors and iveca+vecbi=sqrt(3) then find the value of (veca-vecb).(2veca+vecb)

Let veca and vecb be two non-collinear unit vectors. If vecu=veca-(veca.vecb)vecb and vec=vecaxxvecb , then |vecv| is

veca and vecc are unit collinear vectors and |vecb|=6 , then vecb-3vecc = lambda veca , if lambda is:

The vectors veca and vecb are not perpendicular and vecac and vecd are two vectors satisfying : vecbxxvecc=vecbxxvecd and veca.vecd=0. Then the vecd is equal to (A) vecc+(veca.vecc)/(veca.vecb)vecb (B) vecb+(vecb.vecc)/(veca.vecb)vecc (C) vecc-(veca.vecc)/(veca.vecb)vecb (D) vecb-(vecb.vecc)/(veca.vecb)vecc

IF veca and vecb are no collinear vectors and vecA=(x+4y)veca+(2x+y+1)vecb and vecB=(y-2x+2)vec+(2x-3y-1)vecb, find x and y such that 3vecA=2vecB .

Given three vectors e veca, vecb and vecc two of which are non-collinear. Futrther if (veca + vecb) is collinear with vecc, (vecb +vecc) is collinear with veca, |veca|=|vecb|=|vecc|=sqrt2 find the value of veca. vecb + vecb.vecc+vecc.veca

If veca, vecb and vecc 1 are three non-coplanar vectors, then (veca + vecb + vecc). [(veca + vecb) xx (veca + vecc)] equals

If veca, vecb and vecc 1 are three non-coplanar vectors, then (veca + vecb + vecc). [(veca + vecb) xx (veca + vecc)] equals