[Find by vector method the horizontal force and the force inclined at an angle of `60^@` to the vertical whose resultant is a vertical force P.]

A force of 4N is inclined at an angle of 60^(@) from the vertical. Find out its components along horizontal and vertical directions.

A block of mass m lying on a rough horizontal plance is acted upon by a horizontal force P and another force Q inclined at an angle theta to the vertical. The block will remain in equilibrium, if the coefficient of friction between it and the surface is

A block of mass m lying on a horizontal plane , is acted upon by a horizontal force p and another force Q inclined at an angle theta to the vertical .The block will remain in equilibrium if the coefficient of friction between it and the surface is (assume p gt Q)

A block of mass m lying on a rough horizontal plane is acted upon by a horizontal force P and another force Q inclined at an angle theta to the vertical. The minimum value of coefficient of friction of friction between the block and the surface for which the block will remain in equilibrium is

A wedge of mass m, lying on a rough horizontal plane, is acted upon by a horizontal force F_(1) and another force F_(2) , inclined at an angle theta to the vertical. The block is in equilibrium, then minimum coefficient of friction between it and te surface is

Two forces of 5N and 7N act on a aprticle with an angle of 60^(@) between them. Find the resultant force.

Two forces each of magnitude 2N, act at an angle of 60^(@) . What is the magnitude of the resultant force ?

Resolve horizontally and vertically a force f =8 N which makes an angle of 45^@ with the horizontal.