For any two vectors `veca and vecb` prove that `|veca+vecb|lt+|veca|+|vecb|`

For any two vectors veca and vecb prove that |veca.vecb|lt+|veca||vecb|

For any two vectors veca and vecb prove that |veca+vec|le|veca|+|vecb|

For any two vectors veca and vecb prove that |veca-vec|le|veca|+|vecb|

For any two vectors veca and vecb prove that |veca-vec|ge|veca|-|vecb|

For any two vectors veca and vecb write when | veca + vecb|= | veca-vecb| holds.

For any two vectors vec a\ a n d\ vec b prove that | vec axx vec b|^2=| (veca. veca , veca. vecb),(vecb.veca ,vecb.vecb)|

Find |veca-vecb| , if two vectors veca and vecb are such that |veca|=2,|vecb|=3 and veca.vecb=4 .

Find |veca-vecb| , if two vectors veca and vecb are such that |veca| = 2,|vecb|=3 and veca.vecb = 4 .

If veca and vecb are any two vectors , then prove that |vecaxxvecb|^(2)=|veca|^(2)|vecb|^(2)-(veca.vecb)^(2)=|{:(veca.veca,veca.vecb),(veca.vecb,vecb.vecb):}| or |vecaxxvecb|^(2)+(veca.vecb)^(2)=|veca|^(2)|vecb|^(2) (This is also known as Lagrange identily)

For two vectors veca and vecb,veca,vecb=|veca||vecb| then (A) veca||vecb (B) veca_|_vecb (C) veca=vecb (D) none of these