A paticle acted on by constant forces `4hati=hatj-3hatk and 3hati+hatj-hatk` is displaced from the point `hati+2hatj+3hatk to 5hati+4hatj+hatk`. Find the work done

A particle acted upon by constant forces 4hati +hatj- 4 hatk and 3hati + hatj - hatk is displacment from the point hati+ 2hatj+ hatk to point 5hati + 4hatj +hatk .Total work done by the forces in SI unit is :

A particle is acted upon by constant forces 4hati +hatj - 3hatk and 3hati + hatj -hatk which displace it from a point hati + 2hatj + 3hatk to the point 5hati + 4hatj + hatk . The work done in standard units by the forces is given by:

Find the angle between the vectors 4hati-2hatj+4hatk and 3hati-6hatj-2hatk.

Work done by a force F=(hati+2hatj+3hatk) acting on a particle in displacing it from the point r_(1)=hati+hatj+hatk to the point r_(2)=hati-hatj+hat2k is

Two forces -hati+2hatj-hatk and 2hati-5hatj+6hatk act on a particfle whose position vector is 4hati-3hatj+2hatk and displace it to another point whose positon vector is 6hati+hatj-3hatk . Find the total work done by the force.

A force vecF=10hati+2hatj+3hatk N displaces a particle from vecr_1=2hati+hatj+hatk m to vecr_2=4hati+2hatj+3hatk m Find the work done by the force.

If the vectors 2hati-hatj+hatk,hati+2hatj-3hatk and 3hati+ahatj+5hatk are coplanar, the prove that a=-4.