IF `veca and vecb` re two vectors show that `(vecaxxvecb)^2=a^2b^2-(veca.vecb)^2`

Prove that (vecaxxvecb)^2=veca^2b^2-(veca.vecb)^2 .

If veca and vecb are two vectors , then prove that (vecaxxvecb)^(2)=|{:(veca.veca" ",veca.vecb),(vecb.veca" ",vecb.vecb):}|

If veca and vecb are two vectors , then prove that (vecaxxvecb)^(2)=|{:(veca.veca" ",veca.vecb),(vecb.veca" ",vecb.vecb):}|

If veca and vecb are any two vectors , then prove that |vecaxxvecb|^(2)=|veca|^(2)|vecb|^(2)-(veca.vecb)^(2)=|{:(veca.veca,veca.vecb),(veca.vecb,vecb.vecb):}| or |vecaxxvecb|^(2)+(veca.vecb)^(2)=|veca|^(2)|vecb|^(2) (This is also known as Lagrange identily)

If veca and vecb are two vectors such that |veca|=1, |vecb|=4, veca.vecb=2 . If vecc=(2veca xx vecb)-3vecb , then the angle between veca and vecc is

If veca and vecb asre two vectors such that |veca|=2, |vecb| = 7 and vecaxxvecb=3hati+6hatk find the angle between veca and vecb

If veca and vecb are two vectors, such that veca.vecblt0 and |veca.vecb|=|vecaxxvecb| then the angle between angles between the vectors veca and vecb is

If veca and vecb are two unit vectors, then the vector (veca+vecb)xx(vecaxxvecb) is parallel to the vector

If veca and vecb are two unit vectors such that veca+2vecb and 5veca-4vecb are perpendicular to each other, then the angle between veca and vecb is