Show that the asreas of the parallelogram having diagonals `3hati+hatj-2hatk` and `hati-3hatj+4hatk` is `5sqrt(3)`

Find the area of the parallelogram having diagonals 2hati-hatj+hatk and 3hati+3hatj-hatk

Area of a parallelogram, whose diagonals are 3hati+hatj-2hatk and hati-3hatj+4hatk will be:

Area of a parallelogram, whose diagonals are 3hati+hatj-2hatk and hati-3hatj+4hatk will be :

find the area of a parallelogram whose diagonals are veca=3hati+hatj-2hatk and vecb=hati-3hatj+4hatk .

The area of the parallelogram whose diagonals are the vectors hati+3hatj- 2hatk and 3hati+hatj-4hatk

Show that area of the parallelogram whose diagonals are given by veca and vecb is (|veca xx vecb|)/2 . Also, find the area of the parallelogram, whose diagonals are 2hati - hatj + hatk and hati + 3hatj - hatk .

Show that (veca+vecb)xx(veca-vecb)=-2(vecaxxvecb) and use this result to find the area of a parallelogram whose diagonals are hati-2hatj-3hatk and 2hati-3hatj+2hatk

Determine the area of a parallelogram whose diagonals are given by vectors 3hati+2hatj-7hatk and 5hati+6hatj-3hatk .

If the diagonals of a parallelogram are represented by the vectors 3hati + hatj -2hatk and hati + 3hatj -4hatk , then its area in square units , is