Show that the equation of as line perpendicular to the two vectors `vecb`and `vecc` and passing through point `veca` is `vecr=veca+t(vecbxxvecc)` where t is a scalar.

If vecb is not perpendicular to vecc . Then find the vector vecr satisfying the equation vecr xx vecb = veca xx vecb and vecr. vecc=0

If vecb is not perpendicular to vecc . Then find the vector vecr satisfying the equation vecr xx vecb = veca xx vecb and vecr. vecc=0

If veca is perpendicular to vecb and vecr is a non-zero vector such that pvecr + (vecr.vecb)veca=vecc , then vecr is:

If veca and vecb are mutually perpendicular unit vectors, vecr is a vector satisfying vecr.veca =0, vecr.vecb=1 and (vecr veca vecb)=1 , then vecr is:

Find vector vecr if vecr.veca=m and vecrxxvecb=vecc, where veca.vecb!=0

Let veca and vecb be two non- zero perpendicular vectors. A vector vecr satisfying the equation vecr xx vecb = veca can be

Show that the plane through the points veca,vecb,vecc has the equation [vecr vecb vecc]+[vecr vecc veca]+[vecr veca vecb]=[veca vecb vecc]

Let vecn be a unit vector perpendicular to the plane containing the point whose position vectors are veca, vecb and vecc and, if abs([(vecr -veca)(vecb-veca)vecn])=lambda abs(vecrxx(vecb-veca)-vecaxxvecb) then lambda is equal to

If veca and vecb be two non collinear vectors such that veca=vecc+vecd , where vecc is parallel to vecb and vecd is perpendicular to vecb obtain expression for vecc and vecd in terms of veca and vecb as: vecd= veca- ((veca.vecb)vecb)/b^2,vecc= ((veca.vecb)vecb)/b^2

Show that the perpendicular distance of any point veca from the line vecr=vecb+t vecc is (|(vecb-veca)xxvecc)|/(|vecc|)