If `veca,vecb,vecc` are the position vectors of A,B,C respectively prove that `vecaxxvecb+vecbxxvecc+veccxxveca` is a vector perpendicular to the plane ABC.

Prove that: [vecaxxvecb ,vecbxxvecc ,veccxxveca] = [veca vecb vecc]^2

If veca,vecb,vecc be three vectors such that [veca vecb vec c]=4 then [vecaxxvecb vecbxxvecc veccxxveca] is equal to

If veca+vecb+vecc=0 , prove that (vecaxxvecb)=(vecbxxvecc)=(veccxxveca)

Let veca, vecb and vec c be any three vectors; then prove that [[vecaxxvecb, vecbxxvecc, veccxxveca]] = [[veca, vecb, vecc]]^2

Prove that (vecbxxvecc)xx(veccxxveca)=[veca vecb vecc]vecc

Prove that (vecbxxvecc)xx(veccxxveca)=[veca vecb vecc]vecc

If veca, vecb and vecc are the position vectors of the vertices A,B and C. respectively , of triangleABC . Prove that the perpendicualar distance of the vertex A from the base BC of the triangle ABC is (|vecaxxvecb+vecbxxvecc+veccxxveca|)/(|vecc-vecb|)

If veca,vecb,vecc are the position vectors oif three non collinear points AS,B,C respectively, show that eperpendicular distance of C ferom the line through A and B is (|vecaxxvecb+vecbxxvecc+veccxxveca|)/(|vecb-veca|)

veca,vecb,vecc are the position vectors of vertices A, B, C respectively of a paralleloram, ABCD, ifnd the position vector of D.