Solve: `vecrxxvecb=veca, where veca and vecb` are given vectors such that `veca.vecb=0`.

Solve vecrxxvecb=vecaxxvecb, where veca, vecb are two given vectors

Solve for vec x,vecx xx vec b=veca , where veca,vecb are two given vectors such that veca is perpendicular to vecb .

If (vecaxxvecb)xxvecc=vecaxx(vecbxxvecc) where veca, vecb and vecc are any three vectors such that veca.vecb!=0, vecb. vecc!=0 then veca and vecc are

If (veca xx vecb) xx vecc = veca xx (vecb xx vecc) where veca, vecb and vecc are any three vectors such that veca.vecb =0, vecb.vecc=0 then veca and vecc are:

If (veca xx vecb) xx vecc = vec a xx (vecb xx vecc) , where veca, vecb and vecc are any three vectors such that veca.vecb ne 0, vecb.vecc ne 0 , then veca and vecc are:

A solution of the vector equation vecrxxvecb=vecaxxvecb , where veca, vecb are two given vectors is where lamda is a parameter.

if veca , vecb ,vecc are three vectors such that veca +vecb + vecc = vec0 then

given that veca. vecb = veca.vecc, veca xx vecb= veca xx vecc and veca is not a zero vector. Show that vecb=vecc .

given that veca. vecb = veca.vecc, veca xx vecb= veca xx vecc and veca is not a zero vector. Show that vecb=vecc .

Let vecr, veca, vecb and vecc be four non-zero vectors such that vecr.veca=0, |vecrxxvecb|=|vecr||vecb|,|vecrxxvecc|=|vecr||vecc| then [(veca, vecb, vecc)]=