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If veca=a1 vecl+a2 vecm+a3vecn, vecb=b1 ...

If `veca=a_1 vecl+a_2 vecm+a_3vecn, vecb=b_1 vecl+b_2vecm+b_3vecn and vecc=c_1 vecl+v_2vecm+c_3 vecn where vecl,vecm,vecn` are three non coplnar vectors then show that `[veca vecb vecc]=|(a_1,a_2,a_3),(b_1,b_2,b_3),(c_1,c_2,c_3)|[vecl vecm vecn]`

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