Solve `vecrxxveca=vecb and vecrxxvecc=vecd`.

The condition for equations vecrxxveca = vecb and vecr xx vecc = vecd to be consistent is

If vecaxxvecb=veccxxvecd and vecaxxvecc=vecbxxvecd show that (veca-vecd) is parallel to (vecb-vecc) . It is given that veca!=vecd and vecb!=vecc .

If veca,vecb,vecc,vecd are four distinct vectors satisfying the conditions vecaxxvecb=veccxxvecd and vecaxxvecc=vecbxxecd then prove that veca.vecb+vecc.vecd!=veca.vecc+vecb.vecd

If vecaxxvecb=veccxxvecd and vecaxxvecc=vecbxxvecd then (A) (veca-vecd)=lamda(vecb-vecc) (B) veca+vecd=lamda(vecb+vecc) (C) (veca-vecb)=lamda(vecc+vecd) (D) none of these

Let veca = hati +hatj and vecb = 2hati - hatk then the point of intersection of the lines vecrxxveca = vecbxx veca and vecrxx vecb = vecaxx vecb is

If vecrxxveca=vecbxxveca,vecrxxvecb=vecaxxvecb,veca!=0,vecb!=0,veca!=lamdavecb,veca is not perpendicular to vecb then vecr=

If vecaxxvecb = veccxxvecd and vecaxxvecc = vecbxxvecd , show that (veca-vecd) is parallel to (vecb-vecc) .

If veca, vecb, vecc and vecd ar distinct vectors such that veca xx vecc = vecb xx vecd and veca xx vecb = vecc xx vecd . Prove that (veca-vecd).(vecc-vecb)ne 0, i.e., veca.vecb + vecd.vecc nevecd.vecb + veca.vecc.

Let vecr, veca, vecb and vecc be four non-zero vectors such that vecr.veca=0, |vecrxxvecb|=|vecr||vecb|,|vecrxxvecc|=|vecr||vecc| then [(veca, vecb, vecc)]=

Show that the points whose position vectors are veca,vecb,vecc,vecd will be coplanar if [veca vecb vecc]-[veca vecb vecd]+[veca vecc vecd]-[vecb vecc vecd]=0