For two vectors `veca and vecb,veca,vecb=|veca||vecb|` then (A) `veca||vecb` (B) `veca_|_vecb` (C) `veca=vecb` (D) none of these

If vecasxxvecb=0 and veca.vecb=0 then (A) veca_|_vecb (B) veca||vecb (C) veca=0 and vecb=0 (D) veca=0 or vecb=0

If veca, vecb, vecc are non coplanar vectors such that vecbxxvecc=veca, vecaxxvecb=vecc aned veccxxveca=vecb then (A) |veca|+|vecb|+|vecc|=3 (B) |vecb|=1 (C) |veca|=1 (D) none of these

If |veca+vecb|=|veca-vecb| show that veca_|_vecb .

If |veca|=|vecb| , then (veca+vecb).(veca-vecb) is equal to

If veca is perpendicular to vecb then the vector vecaxx[vecaxx{vecaxx(vecaxxvecb)}] is equla (A) |veca|^2vecb (B) |veca|vecb (C) |veca|^3vecb (D) |veca|^4vecb

If veca and vecb are two non collinear vectors and vecu=veca-(veca.vecb)vecb and vecv=vecaxxvecb then |vecv| is (A) |vecu| (B) |vecu|+|vecu.vecb| (C) |vecu|+|vecu.veca| (D) none of these

If vecc=vecaxxvecb and vecb=veccxxveca then (A) veca.vecb=vecc^2 (B) vecc.veca.=vecb^2 (C) veca_|_vecb (D) veca||vecbxxvecc

The vector veca+vecb bisects the angle between the vectors hata and hatb if (A) |veca|+|vecb|=0 (B) angle between veca and vecb is zero (C) |veca|=|vecb|=0 (D) none of these

Consider three vectors veca, vecb and vecc . Vectors veca and vecb are unit vectors having an angle theta between them For vector veca, |veca|^2=veca.veca If veca_|_vecb and veca_|_vecc then veca||vecbxxvecc If veca||vecb, then veca=tvecb Now answer the following question: The value of sin(theta/2) is (A) 1/2 |veca-vecb| (B) 1/2|veca+vecb| (C) |veca-vecb| (D) |veca+vecb|

Two vectors vecA and vecB are such that vecA+vecB=vecA-vecB . Then