If the angle betweenteh unit vectors `veca and vecb` is vec60^0` then `|veca-vecb|` is (A) 0 (B) 1 (C) 2 (D) 4

If theta is the angle between unit vectors vecA and vecB , then ((1-vecA.vecB))/(1+vecA.vecB)) is equal to

If veca , vecb are unit vectors such that |vec a+vecb|=-1 " then " |2veca -3vecb| =

If veca, vecb are the unit vectors such that veca + 2vecb + 2vecc=0 , then |veca xx vecc| is equal to:

If veca,vecb,vecc are unit vectors such that veca+vecb+vecc=0 then veca.vecb+vecb.vecc+vecc.veca= (A) 3/2 (B) -3/2 (C) 2/3 (D) 1/2

The non zero vectors veca,vecb and vecc are related by veca=(8) vecb and vecc=-7vecb. Then angle between veca and vecc is (A) pi/2 (B) pi (C) 0 (D) pi/4

If veca and vecb are unit vectors, then the greatest value of |veca +vecb|+ |veca -vecb| is

Consider three vectors veca, vecb and vecc . Vectors veca and vecb are unit vectors having an angle theta between them For vector veca, |veca|^2=veca.veca If veca_|_vecb and veca_|_vecc then veca||vecbxxvecc If veca||vecb, then veca=tvecb Now answer the following question: If vecc is a unit vector and equal to the sum of veca and vecb the magnitude of difference between veca and vecb is (A) 1 (B) sqrt(2) (C) sqrt(3) (D) 1/sqrt(2)

If veca and vecb are unit vectors inclined at an angle theta , then the value of |veca-vecb| is

Let, veca , vecb and vecc be three non zero vectors such that vecc is a unit vector perpendicular to both veca and vecb. if the angle between veca and vecb is pi//6, prove that [vec a vecb vecc ]^(2) =1/4 |veca|^(2)|vecb|^(2)

The vector veca+vecb bisects the angle between the vectors hata and hatb if (A) |veca|+|vecb|=0 (B) angle between veca and vecb is zero (C) |veca|=|vecb|=0 (D) none of these