If `veca,vecb,vecc` are unity vectors such that `vecd=lamdaveca+muvecb+gammavecc` then gamma is equal to (A) `([veca vecb vecc])/([vecb veca vecc])` (B) `([vecb vecc vecd])/([vecb vecc veca])` (C) `([vecb vecd vecc])/([veca vecb vecc])` (D) `([vecc vecb vecd])/([veca vecb vecc])`

If veca, vecb, vecc are vectors such that veca.vecb=0 and veca + vecb = vecc then:

If vecA=(vecbxxvecc)/([vecb vecc vecc]), vecB=(veccxxveca)/([vecc veca vecb)], vecC=(vecaxxvecb)/([veca vecb vecc)] find [vecA vecB vecC]

The vectors veca and vecb are not perpendicular and vecac and vecd are two vectors satisfying : vecbxxvecc=vecbxxvecd and veca.vecd=0. Then the vecd is equal to (A) vecc+(veca.vecc)/(veca.vecb)vecb (B) vecb+(vecb.vecc)/(veca.vecb)vecc (C) vecc-(veca.vecc)/(veca.vecb)vecb (D) vecb-(vecb.vecc)/(veca.vecb)vecc

Prove that [[veca, vecb + vecc, vecd]] = [[veca, vecb, vecd]] + [[veca, vecc, vecd]]

If veca,vecbandvecc are unit vectors such that veca+vecb+vecc=0 , then the value of veca.vecb+vecb.vecc+vecc.veca is

If veca, vecb, vecc are three non-zero vectors such that veca + vecb + vecc=0 and m = veca.vecb + vecb.vecc + vecc.veca , then:

If vec a,vec b , vec c are unit vectors such that veca + vec b+ vecc = 0 and lambda = veca.vecb + vecb.vecc+vecc.veca and d = veca xx vecb + vecb xx vecc + vecc xx veca , then (lambda,vecd) is

If veca, vecb, vecc are any three vectors such that (veca+vecb).vecc=(veca-vecb)=vecc=0 then (vecaxxvecb)xxvecc is

If veca , vecb and vecc are three vectors such that vecaxx vecb =vecc, vecb xx vecc= veca, vecc xx veca =vecb then prove that |veca|= |vecb|=|vecc|

If veca , vecb and vecc are three vectors such that vecaxx vecb =vecc, vecb xx vecc= veca, vecc xx veca =vecb then prove that |veca|= |vecb|=|vecc|