If vectors `veca and vecb` are two adjacent sides of parallelograsm then the vector representing the altitude of the parallelogram which is perpendicular to `veca` is (A) `vecb+(vecbxxveca)/(|veca|^2)` (B) `(veca.vecb)/(vecb|^2)` (C) `vecb-(vecb.veca)/(|veca|)^2)` (D) `(vecaxx(vecbxxveca))/(vecb|^20`

The distance of the point A(veca) from the line vecr=vecb+tvecc is (A) |(veca-vecb)xxvecc| (B) (|(veca-vecb)xxvecc|)/(|(veca-vecb)|) (C) (|(veca-vecb)xxvecc|)/(|vecc|) (D) (|vecaxx(vecb-vecc)|)/(|veca|)

The resolved part of the vector veca along the vector vecb is veclamda and that perpendicular to vecb is vecmu . Then (A) veclamda=((veca.vecb).veca)/veca^2 (B) veclamda=((veca.vecb).vecb)/vecb^2 (C) vecmu=((vecb.vecb0veca-(veca.vecb)vecb)/vecb^2 (D) vecmu=(vecbxx(vecaxxvecb))/vecb^2

Show that (veca xx vecb)^(2) = |veca| ^(2) |vecb|^(2) - (veca.vecb)^(2) = |(veca.veca)/(veca. vecb)(veca.vecb)/(vecb.vecb)|

If veca is perpendicular to vecb then the vector vecaxx[vecaxx{vecaxx(vecaxxvecb)}] is equla (A) |veca|^2vecb (B) |veca|vecb (C) |veca|^3vecb (D) |veca|^4vecb

If vecc=vecaxxvecb and vecb=veccxxveca then (A) veca.vecb=vecc^2 (B) vecc.veca.=vecb^2 (C) veca_|_vecb (D) veca||vecbxxvecc

The vectors veca and vecb are not perpendicular and vecac and vecd are two vectors satisfying : vecbxxvecc=vecbxxvecd and veca.vecd=0. Then the vecd is equal to (A) vecc+(veca.vecc)/(veca.vecb)vecb (B) vecb+(vecb.vecc)/(veca.vecb)vecc (C) vecc-(veca.vecc)/(veca.vecb)vecb (D) vecb-(vecb.vecc)/(veca.vecb)vecc

If veca and vecb be two non collinear vectors such that veca=vecc+vecd , where vecc is parallel to vecb and vecd is perpendicular to vecb obtain expression for vecc and vecd in terms of veca and vecb as: vecd= veca- ((veca.vecb)vecb)/b^2,vecc= ((veca.vecb)vecb)/b^2

If veca and vecb are two vectors, such that |veca xx vecb|=2 , then find the value of [veca vecb veca xx vecb]

If veca and vecb are two vectors, such that |veca xx vecb|=2 , then find the value of [veca vecb veca xx vecb]