If `veca,vecb and vecc` are non coplnar and non zero vectors and `vecr` is any vector in space then`[vecc vecr vecb]veca+pveca vecr vecc] vecb+[vecb vecr veca]c=` (A) `[veca vecb vecc]` (B) `[veca vecb vecc]vecr` (C) `vecr/([veca vecb vecc])` (D) `vecr.(veca+vecb+vecc)`

If veca,vecb and vecc are three non coplanar vectors and vecr is any vector in space, then (vecaxxvecb)xx(vecrxxvecc)+(vecb xxvecc)xx(vecrxxveca)+(veccxxveca)xx(vecrxxvecb)= (A) [veca vecb vecc] (B) 2[veca vecb vecc]vecr (C) 3[veca vecb vecc]vecr (D) 4[veca vecb vecc]vecr

veca , vecb and vecc are three non-coplanar vectors and vecr . Is any arbitrary vector. Prove that [vecbvecc vecr]veca+[vecc veca vecr]vecb+[vecavecbvecr]vecc=[veca vecb vecc]vecr .

If veca, vecb, vecc are three non-zero non-null vectors are vecr is any vector in space then [(vecb, vecc, vecr)]veca+[(vecc, veca, vecr)]vecb+[(veca, vecb, vecr)]vecc is equal to

veca,vecb and vecc are three non-coplanar vectors and r is any arbitrary vector. Prove that [[vecb, vecc,vec r]]veca + [[vecc, veca, vecr]]vecb +[[veca,vec b,vec r]]vecc = [[veca,vec b, vecc]]vecr

Statement 1: Let vecr be any vector in space. Then, vecr=(vecr.hati)hati+(vecr.hatj)hatj+(vecr.hatk)hatk Statement 2: If veca, vecb, vecc are three non-coplanar vectors and vecr is any vector in space then vecr={([(vecr, vecb, vecc)])/([(veca, vecb, vecc)])}veca+{([(vecr, vecc, veca)])/([(veca, vecb, vecc)])}vecb+{([(vecr, veca, vecb)])/([(veca, vecb, vecc)])}vecc

If vecb and vecc are any two orthogonal unit vectors and veca is any vector, then (veca.vecb)vecb + (veca.vecc)vecc + (veca.(vecb xx vecc))/|vecb xx vecc|^(2) (vecb xx vecc) =

If vecA=(vecbxxvecc)/([vecb vecc vecc]), vecB=(veccxxveca)/([vecc veca vecb)], vecC=(vecaxxvecb)/([veca vecb vecc)] find [vecA vecB vecC]

If veca,vecb and vecc are three mutually perpendicular unit vectors then (vecr.veca)veca+(vecr.vecb)vecb+(vecr.vecc)vecc= (A) ([veca vecb vecc]vecr)/2 (B) vecr (C) 2[veca vecb vecc] (D) none of these