The two lines vecr=veca+veclamda(vecbxxv...

The two lines `vecr=veca+veclamda(vecbxxvecc) and vecr=vecb+mu(veccxxveca)` intersect at a point where `veclamda and mu` are scalars then (A) `veca,vecb,vecc` are non coplanar (B) `|veca|=|vecb|=|vecc|` (C) `veca.vecc=vecb.vecc` (D) `lamda(vecb xxvecc)+mu(vecc xxveca)=vecc`

Similar Questions

Explore conceptually related problems

If vector veca,vecb,vecc are coplanar show that |(veca,vecb,vecc),(veca.veca,veca.vecb,veca.vecc),(vecb.veca,vecb.vecb,vecb.vecc)|

If veca, vecb, vecc are vectors such that |vecb|=|vecc| then {(veca+vecb)xx(veca+vecc)}xx(vecbxxvecc).(vecb+vecc)=

If veca, vecb, vecc are any three non coplanar vectors, then (veca+vecb+vecc).(vecb+vecc)xx(vecc+veca)

If the vectors veca, vecb, and vecc are coplanar show that |(veca,vecb,vecc),(veca.veca, veca.vecb,veca.vecc),(vecb.veca,vecb.vecb,vecb.vecc)|=0

If veca, vecb, vecc are non-null non coplanar vectors, then [(veca-2vecb+vecc, vecb-2vecc+veca, vecc-2veca+vecb)]=

If veca, vecb, vecc are non coplanar non null vectors such that [(veca, vecb, vecc)]=2 then {[(vecaxxvecb, vecbxxvecc, veccxxveca)]}^(2)=

If veca, vecb, vecc are non-coplanar vectors, then (veca.(vecbxxvecc))/((veccxxveca).vecb)+(vecb.(vecaxxvecc))/(vecc.(vecaxxvecb)) is equal to

If veca, vecb, vecc are any three non coplanar vectors, then [(veca+vecb+vecc, veca-vecc, veca-vecb)] is equal to

If the three vectors veca,vecb,vecc are non coplanar express each of vecbxxvecc, veccxxveca, vecaxxvecb in terms of veca,vecb,vecc .

If veca,vecb,vecc are coplanar, show that veca+vecb, vecb+vecc, vecc+veca are also coplanar.