If `|veca|=and |vecb|=3 and veca.vecb=0 ,then (veca(vecx(vecaxx(vecaxx))))=` (A) `48hatb` (B) `-48hatb` (C) `48hata` (D) `-48hata`

If |veca|=2 and |vecb|=3 and veca.vecb=0, " then " (vecaxx(vecaxx(vecaxx(vecaxxvecb)))) is equal

If |veca|=2, |vecb|=5 and veca*vecb=0 , then veca xx (vecaxx(vecaxx(vecaxx(vecaxx(veca xx vecb))))) is equal to :

If vecasxxvecb=0 and veca.vecb=0 then (A) veca_|_vecb (B) veca||vecb (C) veca=0 and vecb=0 (D) veca=0 or vecb=0

If |veca|=4,|vecb|=2 and angle between veca and vecb is pi/6 then (vecaxxvecb)^2 is (A) 48 (B) (veca)^2 (C) 16 (D) 32

Prove that (veca+3vecb)xx(veca+vecb)+(3veca-5vecb)xx(veca-vecb)=0

Find the value of (veca+vecb)xx[vecaxx((veca-vecb)xxvecb)]

Prove that: vecaxx[vecbxx(veccxxveca)]=(veca.vecb)(vecaxxvecc)

A parallelogram is constructed on 3veca+vecb and veca-4vecb, where |veca|=6 and |vecb|=8 and veca and vecb are anti parallel then the length of the longer diagonal is (A) 40 (B) 64 (C) 32 (D) 48

Prove that vecaxx(vecb+vecc)+vecbxx(vecc+veca)+veccxx(veca+vecb)=0

If veca,vecb,vecc are unit vectors such that veca+vecb+vecc=0 then veca.vecb+vecb.vecc+vecc.veca= (A) 3/2 (B) -3/2 (C) 2/3 (D) 1/2