If `veca,vecb,vecc` are any thre vectors then `(vecaxxvecb)xxvecc` is a vector (A) perpendicular to `vecaxxvecb` (B) coplanar with `veca and vecb` (C) parallel to `vecc` (D) parallel to either `veca or vecb`

If veca, vecb, vecc, vecd are coplanar vectors, then (vecaxxvecb)xx(veccxxvecd)=

If veca, vecb, vecc are any three vectors such that (veca+vecb).vecc=(veca-vecb)=vecc=0 then (vecaxxvecb)xxvecc is

If veca,vecb,vecc,vecd are any for vectors then (vecaxxvecb)xx(veccxxvecd) is a vector (A) perpendicular to veca,vecb,vecc,vecd (B) along the the line intersection of two planes, one containing veca,vecb and the other containing vecc,vecd . (C) equally inclined both vecaxxvecb and veccxxvecd (D) none of these

If veca, vecb, vecc are any three non coplanar vectors, then [(veca+vecb+vecc, veca-vecc, veca-vecb)] is equal to

If veca, vecb, vecc are any three non coplanar vectors, then (veca+vecb+vecc).(vecb+vecc)xx(vecc+veca)

For any three vectors veca,vecb,vecc their product would be a vector if one cross product is folowed by other cross product i.e (vecaxxvecb)xxvecc or (vecbxxvecc)xxveca etc. For any four vectors veca,vecb,vecc,vecd the product would be a vector with the help of sequential cross product or by cross product of two vectors obtained by corss product of two pair i.e. (vecaxx(vecbxxvecc))xxvecd or (vecaxxvecb)xx(veccxxvecd). Now answer the following question: (vecaxxvecb)x(veccxxvecd) would be a vector (A) perpendicular to veca,vecb,vecc,vecd (B) parallel to veca and vecc (C) paralel to vecb and vecd (D) none of these

The vector (veca.vecb)vecc-(veca.vecc)vecb is perpendicular to

veca,vecb,vecc are non zero vectors. If vecaxxvecb=vecaxxvecc and veca.vecb=veca.vecc then show that vecb=vecc .

If veca, vecb, vecc are vectors such that veca.vecb=0 and veca + vecb = vecc then:

If veca, vecb, vecc are non-null non coplanar vectors, then [(veca-2vecb+vecc, vecb-2vecc+veca, vecc-2veca+vecb)]=