[" 13.Th.st."-11,-8,-5,......,49-(1)/(4n)" sitar "(4s(.)/(6)" ."],[[" (A) "37," (B) "40],[" (C) "43," (D) "58]]

If S_(1) = {2}, S_(2) = { (3)/(2) , (4)/(2) }, S_(3) = { (4)/( 4) , (5)/(4) , (6)/( 4) } , S_(4) = { (5)/( 8) , (6)/( 8) , (7)/(8) , (8)/( 8) } ,….. then the sum of numbers in S_(20) is

The 4th term from the end of the A.P.-11,-8,-5,….49 is a)37 b)40 c)43 d)58

(11)/(6)times(8)/(11)-(4)/(8)-(11)/(3)+(5)/(4)

2.5+3.8+4.11+.....+ upto n terms =n(n^(2)+4n+5), n in N

The 4th term from the end of an AP -11, -8, -5, …, 49 is

The 4th term from the end of an AP -11, -8, -5, …, 49 is

(1)/(2.5)+(1)/(5.8)+(1)/(8.11)+... n terms =(A)(n)/(6n+4) (B) (n)/(3n+2)(C)(n)/(4n+6)(D)(1)/(2(2n+3))

If 4th term in the expansion of (kx+ 1/x)^n is 5/2 then (A) n=8 (B) n=6 (C) k=1/4 (D) k=1/2

In the binomial expansion of (a-b)^(n),n>=5 the sum of 5 th and 6 th terms is zero,then (a)/(b) equals (1)(5)/(n-4) (2) (6)/(n-5) (3) (n-5)/(6) (4) (n-4)/(5)