Find the reflection of the point `(alpha, beta, gamma)` in the XY-plane, YZ-plane and ZX plane.

reflection of the point (alpha, beta, gamma) in the XY-plane is :

Find the the image of the point (alpha, beta, gamma) with respect to the plane 2x+y+z=6 .

A plane meets the coordinates axis in A, B, C such that the centroid of the triangle ABC is the point (alpha, beta, gamma) . Find the equation of plane in intercept form.

The equation to the perpendicular from the point (alpha, beta gamma) to the plane ax+by+cz+d=0 is

find the reflection of P(x,y,z) in the (i) XY plane (ii) YZ plane (iii) ZX plane

Let A, B, C be the feet of perpendiculars from point P(1, –2, –3) on the xy-plane, yz-plane and xz-plane respectively. Find the coordinates of A, B, C.

Statement 1: If point (alpha, beta, gamma) lies above the plane (a^(2)+1)x+(b+1)y+(c^(2)+c+1)z+d=0 , then (a^(2)+1)alpha+(b+1)beta+(c^(2)+c+1)gamma+d gt 0 . because Statement 2: If the point (alpha, beta, gamma) lies above the plane ax+by+cz+d=0 then (a alpha+b beta+c gamma+d)/( c )gt 0 .

Find the image of the point (4, 5, 7) in XY-plane.

If the image of the point ( 1,-2,3) in the plane 2x + 3y -z =7 is the point ( alpha, beta , gamma ), then the value of alpha + beta + gamma is equal to