The vertices of a triangle are `A(5,4,6),B(1,-1,3) and (4,3,2)`. The internal bisector of `/_BAC `meets BC in D. Find AD.

The vertices f the triangle are A(5,4,6), B(1,-1,3)n a d C(4,3,2)dot The internal bisector of angle A meets BC at D. Find the coordinates of D and the length AD.

The vertices of a triangle are A(-1,-7),B(5,1) and C(1,4) .If the internal angle bisector of /_B meets the side AC in D, then find the length AD.

The vertices of a triangle are A(1,1,2),B(4,3,1) and C(2,3,5). The vector representing internal bisector of the angle A is

The vertices of a triangle are A(3,4),B(-4,3),C(4,3). The altitude from A on BC meets the circumcircle at

The vertices of a triangle ABC are are A(1,3,5),B(-2,4,7) and C(3,2,2). Then the direction cosines of the vector along bisector of /_BAC is

The vertices of a triangle are A(1,1,2),B(4,3,1) and C(2,3,5) Vectors representing the internal & external bisectors of the angle A are: