The distance of the point `(1,-2,3)` from the plane `x-y+z=5` measured parallel to the line `x/2=y/3=z/-6`, is

The distance of the point (1,-2,3) from the plane x-y+z-5=0 , measured parallel to the line x/2=y/3=(z-1)/-6 is equal to

Find the distance of the point (1,-2,3) from the plane x-y+z=5 measured parallel to the line (x-1)/2=(y-3)/3=(z+2)/-6 .

The distance of point (1,-2,-3) from plane x-y+z=5 measured parallel to the line x/2=y/3=z/(-6) is

Find the distance of the point (1,-2,3) from the plane x - y + z = 5, measured parallel to the line : (x)/(2) = (y)/(3) = (z)/(-6) .

Find the distance of the point (3,4,5) from the plane x+y+z=2 measured parallel to the line 2x=y=z

Find the distance of the point (1,0,-3) from the plane x-y-z=9 measured parallel to the line (x-2)/(2)=(y+2)/(2)=(z-6)/(-6)

Find the distance of the point (3,4,5) from the plane x+y+z=2 , measured parallel to the line 2x=y=z .

The distance of the point (1,-5,9) from the plane x-y+z=5 measured along the line x=y=z is

Find the distance of the point(1, 0, -3) from the plane x-y-z=9 measured parallel to the line, (x-2)/(2)=(y+2)/(3)=(z-6)/(-6) .