Find the equation of the plane which is at a distance of 5 units fom the origin and perpendiculat to `2hati-3hatj+6hatk`

Find the vector equation of a plane which is at a distance of 4 units from the origin and which has (2hati-3hatj+6hatk) as the normal vector.

Find th equation of the plane which is at distance of 8 units from origin and the perpendicular vector from origin to this plane is (2hati+hatj-2hatk) .

Find the equation of the plane which is at a distance of sqrt(29) units from origin and the perpendicular vector from oiring to this plane is (4hati-2hatj+3hatk) .

Find the vector equation of the plane which is at a distance of 5 units from the origin and which is normal to the vector 2hati + hatj + 2hatk .

Find the vector equation of a plane which is at a distance of 7 units from the origin and which is normal to the vector 3 hati + 5 hatj - 6 hatk . (ii) Find the vector equation of a plane , which is at a distance of 5 units from the origin and its normal vector is 2 hati - 3 hatj + 6 hatk .

Find the vector equation of a plane which is at a distance of 7 units from the origin and normal to the vector 3hati+5hatj-6hatk

Find the vector equation of the plane which is at a distance of 6 units from the origin and which is normal to the vector 2hati - hatj + 2hatk .

Find the vector equation of a plane which is at a distance of 5 units from the origin and whose normal vector is 2 hati - hatj + 2 hatk .

The vector form of the equation of the plane which is at a distance of 3 units from the origin and has hati + hatj - 3hatk as a normal vector, is

The vector equation of the plane which is at a distance of 8 units from the origin which is normal to the vector 2hati+hatj+2hatk is