Find the equation of the plane passing through the line intersection of the plane: `2x-y=0 and 3z-y=0` and perpendicular to the plane `4x+5y-3z=8`

Find the equation of the plane passing through the line of intersection of the planes 2x-y=0 and 3z-y=0 , and perpendicular to the plane 4x+5y-3z=9 .

Let P=0 be the equation of a plane passing through the line of intersection of the planes 2x-y=0 and 3z-y=0 and perpendicular to the plane 4x+5y-3z=8. Then the points which lie on the plane P=0 is/are a.(0,9,17) b.(1/7,21/9) c.(1,3,-4) d.(1/2,1,1/3)

Find the equation of the plane passing through the intersection of the planes 2x-3y+z-4=0 and x-y+z+1=0 and perpendicular to the plane x+2y-3z+6=0

The equation of the plane passing through the line of intersection of the planes x+y+z=6 and 2x+3y+4z+5=0 and perpendicular to the plane 4x+5y-3z=8 is

Find the equation of the plane passing through the intersection of the planes 2x+3y-z+1=0 and x+y-2z+3=0 and perpendicular to the plane 3x-y-2z-4=0

Find the equation of the plane through the line of intersection of the planes x+2y+3z+2=0 , 2x+3y-z+3=0 and perpendicular to the plane x+y+z=0

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and which is perpendicular to the plane x-y+z=0

The equation of the plane passing through the line of intersection of the planes x+y+z=1,2x+3y+4z=7 , and perpendicular to the plane x-5y+3z=5 is given by

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to the plane x-y+z=0