Find the equation of the line of intersection of the planes `4x + 4y - 5z = 12, 8x + 12y - 13z = 32` in the symmetric form.

Find the equation of the line of intersection of the planes 5z=12,8x+12y-13z=32 in the symmetric form.

The equation of the line of intersection of the planes x+2y+z=3 and 6x+8y+3z=13 can be written as

The equation of the line intersection of the planes 4x+4y-5z=12 and 8x+12y-13z=32 can be written as: (A) x/2=(y-1)/3=(z-2)/4 (B) x/2=y/3=(z-2)/4 (C) (x-1)/2=(y-2)/3=z/4 (D) (x-1)/2=(y-2)/(-3)=z/4

Find the equation of the plane through the intersection of the planes 3x-4y+5z=10 and 2x+2y-3z=4 and parallel to the line x=2y=3z

The equation of the plane passing through the line of intersection of the planes x + y + 2z = 1,2x + 3y + 4z = 7, and perpendicular to the plane x - 5y + 3z = 5 is given by:

Find the equation of the plane passing through the line of intersection of the planes : 2x + y - z = 3 and 5x - 3y + 4z = 9 and parallel to the line (x -1)/(2) = (y - 3)/(4) = (z -5)/(5) .