Find the intercepts of tehplane `3x+4y-7z=84` on the axes. Also find the length of perpendicular from origin to this plane and direction cosines of this normal.

The length of the perpendicular from origin to the plane x-3y+4z=6 is

Find the normal form of the plane x+2y-2z+6=0 . Also find the length of perpendicular from origin to this plane and the d.c.'s of the normal.

Find the d.c.'s of the normal and length of perpendicular from origin to the plane x=2 .

A plane cuts off intercepts 3,-4,6 on the coordinate axes. The length of perpendicular from the origin to this plane is

Convert the line 3x-4y+5=0 into perpendicular form and find the length of perpendicular from origin to this line.

Reduce the equation 2x-3y-6z=14 to the normal form and hence fine the length of perpendicular from the origin to the plane. Also, find the direction cosines of the normal to the plane.

Reduce the equation of the plane x-2y-2z=12 to normal form and hence find the length of the perpendicular for the origin to the plane. Also, find the direction cosines of the normal to the plane.

Find the normal form of the plane 2x+3y-z = 5 . Also find the length of perpendicular from origin and d.c's of the normal to the plane.

If a plane, intercepts on the coordinates axes at 8,4,4 then the length of the perpendicular from the origin to the plane is