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Find the equation of the plane which con...

Find the equation of the plane which contains the line of intersection of the planes `vecr.(hati+2hatj+3hatk)-4=0, vecr.(2hati+hatj-hatk)+5=0` and which is perpendicular to the plane `vecr.(5hati+3hatj-6hatk)+8=0`

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Find the equation of the plane , which contains the line of intersection of the planes : vec(r). (hati + 2 hatj + 3 hatk) -4 = 0 and vec(r). (2 hati + hatj + hatk) + 5 = 0 and which is perpendicular to the plane : vec(r) . (5 hati + 3 hatj - 6 hatk) ) + 8 = 0 .

The line of intersection of the planes vecr . (3 hati - hatj + hatk) =1 and vecr. (hati+ 4 hatj -2 hatk)=2 is:

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Find the equation of the plane passing through the line of intersection of the planes vecr.(hati+hatj+hatk)=1 and vecr.(2hati+3hatj-hatk)+4=0 and parallel to x-axis.

Find the equation of the plane passing through the intersection of the planes vecr.(2hati+hatj+3hatk)=7 , vecr.(2hati+5hatj+3hatk)=9 and the point (2,1,3) .

Find the equation of the plane passing through the intersection of the planes vecr.(2hati+hatj+3hatk)=7, vecr.(2hati+5hatj+3hatk)=9 and the point (3,2,-1) .

The angle between hati and line of the intersection of the plane vecr.(hati+2hatj+3hatk)=0andvecr.(3hati+3hatj+hatk)=0 is

Find the equation of the plane passing through the line of intersection of the planes vecr.(hati+3hatj)-6=0 and vecr.(3hati-hatj-4hatk)=0 , whose perpendicular distance from the origin is unity.