The equation of plane parallel to the plane `x+y+z=0` and passing through `(alpha, beta, gamma0` is (A) `x+y+z=alpha+beta+gamma` (B) `x+y+z=alphabeta+betagamma+gammaalpha` (C) `x+y+z+alpha+beta+gamma=0` (D) none of these

The equation of the plane which makes with coordinate axes a triangle with its centroid (alpha, beta, gamma) is (A) alphax+betay+gammaz=3 (B) x/alpha+y/gamma+z/gamma=1 (C) alphax+betay+gammaz=1 (D) x/alpha+y/beta+z/gamma=3

The equations of the line through the point (alph, beta, gamma) and equally inclined to the axes are (A) x-alphay-beta=z-gamma (B) (x-1)/alpha=(y-1)/beta=(z-1)/gamma (C) x/alpha=y/beta=z/gamma (D) none of these

Show that | (1,1,1), (alpha ^ 2, beta ^ 2, gamma ^ 2), (alpha ^ 3, beta ^ 3, gamma ^ 3) | = (alpha-beta) (beta-gamma) (gamma-alpha) (alphabeta + betagamma + gammaalpha) |

If alpha,beta,gamma are the roots of x^(3)+2x^(2)+3x+8=0 then (alpha+beta)(beta+gamma)(gamma+alpha)=

If alpha,beta,gamma are the cube roots of p, then for any x,y,z(x alpha+y beta+z gamma)/(x beta+y gamma+z alpha)=

A line makes angles alpha, beta, gamma with X, Y, Z axes respectively. If alpha=beta and gamma=45^(@) , then alpha+beta+gamma=

If the image of the point ( 1,-2,3) in the plane 2x + 3y -z =7 is the point ( alpha, beta , gamma ), then the value of alpha + beta + gamma is equal to

If alpha, beta, gamma are roots of x^(3)-2x^(2)+7x-1=0 then the value of (alpha+beta-gamma) (beta+gamma-alpha) (alpha+gamma-beta)