The line of intersection of the planes `vecr.(3hati-hatj+hatk)=1` and `vecr.(hati+4hatj-2hatk)=2` is parallel to the vector (A) `2hati+7hatj+13hatk` (B) `-2hati+7hatj+13hatk` (C) `-2hati-7hatj+13hatk` (D) `2hati-7hatj-13hatk`

The line of intersection of the planes vecr . (3 hati - hatj + hatk) =1 and vecr. (hati+ 4 hatj -2 hatk)=2 is:

The angle between the planes vecr.(2hati-hatj+hatk)=6 and vecr.(hati+hatj+2hatk)=5 is

The vector parallel to the line of intersection of the planes vecr.(3hati-hatj+hatk) = 1 and vecr.(hati+4hatj-2hatk)=2 is :

Find the angle between the planes vecr.(3hati-4hatj+5hatk)=0 and vecr.(2hati-hatj-2hatk)=7 .

Find the angle between the planes. vecr.(hati+hatj+2hatk)=5 and vecr.(2hati-hatj+hatk)=8 .

The plane through the point (-1,-1,-1) nd contasining the line of intersection of the planes vecr.(hati+3hatj-hatk)=0 ,vecr.(hati+2hatk)=0 is (A) vecr.(hati+2hatj-3hatk)=0 (B) vecr.(hati+4hatj+hatk)=0 (C) vecr.(hati+5hatj-5hatk)=0 (D) vecr.(hati+hatj+3hatk)=0

Show that the line vecr=(2hati-2hatj+3hatk)+lambda(hati-hatj+4hatk) is parallel to the plane vecr.(hati+5hatj+hatk)=7 .

Equation of a plane passing through the intersection of the planes vecr.(3hati-hatj+hatk)=1 and vecr.(hati+4hatj-2hatk)=2 and passing through the point (hati+2hatj-hatk) is :

Find the points of intersection of the line vecr = 2hati - hatj + 2hatk + lambda(3hati + 4hatj + 2hatk) and the plane vecr.(hati - hatj + hatk) = 5