The equation of the line intersection of the planes `4x+4y-5z=12 and 8x+12y-13z=32` can be written as: (A) `x/2=(y-1)/3=(z-2)/4` (B) `x/2=y/3=(z-2)/4` (C) `(x-1)/2=(y-2)/3=z/4` (D) `(x-1)/2=(y-2)/(-3)=z/4`

Find the equation of the plane through the intersection of the planes 3x-4y+5z=10 and 2x+2y-3z=4 and parallel to the line x=2y=3z

Find the equation of the plane passing through the line of intersection of the planes 4x-5y-4z=1 and 2x=y+2z=8 and the point (2,1,3).

Equation of theine passing through hati+hatj-3hatk and perpendiculr to the plane 2x-4y+3z+5=0 is (A) (x-1)/2=(1-y)/(-4)=(z-3)/3 (B) (x-1)/2=(1-y)/4=(z+3)/3 (C) (x-2)/1=(y+4)/1)=(z-3)/3 (D) (x-1)/(-2)=(1-y)/(-4)=(z-3)/3

Which of the following line is passing through point of intersection of line (x-4)/(2)=(y-3)/(2)=(z-5)/(1) and the plane x+y+z=2( a) (x)/(2)=(y+1)/(3)=(z-3)/(4) (b) (x-2)/(3)=(y-1)/(3)=(z-2)/(2)(c)(x-2)/(2)=(y+1)/(3)=(z-2)/(4)(d)(x-2)/(2)=(y+1)/(3)=(z+3)/(4)